fix: allow for shorter arrays in isSorted

Also add some style changes
This commit is contained in:
Aleksei Lymar
2020-10-12 21:55:18 +03:00
committed by GitHub
parent 805c6bd36c
commit 010be0b89b

View File

@ -3,20 +3,19 @@ title: isSorted
tags: array,intermediate
---
Returns `1` if the array is sorted in ascending order, `-1` if it is sorted in descending order or `0` if it is not sorted.
Returns `1` if an array of numbers is sorted in ascending order, `-1` if it is sorted in descending order or `0` if it is not sorted.
- Calculate the ordering `direction` for the first two elements.
- Use `Object.entries()` to loop over array objects and compare them in pairs.
- Return `0` if the `direction` changes or the `direction` if the last element is reached.
- Calculate the ordering `direction` for every pair of adjacent array elements.
- Return `0` if the `direction` changes or the `direction` sign if the last element is reached.
```js
const isSorted = arr => {
let direction = -(arr[0] - arr[1]);
for (let [i, val] of arr.entries()) {
direction = !direction ? -(arr[i - 1] - arr[i]) : direction;
if (i === arr.length - 1) return !direction ? 0 : direction / Math.abs(direction);
else if ((val - arr[i + 1]) * direction > 0) return 0;
let direction = 0;
for (let i = 1; i < arr.length; i++) {
if (!direction) direction = arr[i] - arr[i - 1];
else if ((arr[i] - arr[i - 1]) * direction < 0) return 0;
}
return Math.sign(direction);
};
```
@ -24,4 +23,5 @@ const isSorted = arr => {
isSorted([0, 1, 2, 2]); // 1
isSorted([4, 3, 2]); // -1
isSorted([4, 3, 5]); // 0
isSorted([4]); // 0
```