update snippets 62-78
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@ -6,5 +6,8 @@ Create a `Set` from `b`, then use `Array.filter()` on `a` to only keep values co
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```js
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const intersection = (a, b) => { const s = new Set(b); return a.filter(x => s.has(x)); };
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// intersection([1,2,3], [4,3,2]) -> [2,3]
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```
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```js
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intersection([1,2,3], [4,3,2]) -> [2,3]
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```
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