diff --git a/snippets/vectorAngle.md b/snippets/vectorAngle.md
index ce218fde1..336277285 100644
--- a/snippets/vectorAngle.md
+++ b/snippets/vectorAngle.md
@@ -1,28 +1,23 @@
 ---
 title: vectorAngle
-tags: math, beginner
+tags: math,beginner
 ---
 
-Returns the angle (theta) value between two vectors.
+Returns the angle (theta) between two vectors.
 
-Use `Math.trunc()` to convert the half of `length` to integer. 
-Use `Array.prototype.slice()` slice the incoming array into two vectors. 
 Use `Array.prototype.reduce()`, `Math.pow()` and `Math.sqrt()` to calculate the magnitude of each vector and the scalar product of the two vectors.
-Use `Math.acos()` to calculate arccos and get the theta.
+Use `Math.acos()` to calculate the arccos and get the theta value.
 
 
 ```js
-const vectorAngle = (...x) =>{ 
-  let half = Math.trunc(x.length / 2);
-  let [a, b] = [x.slice(0, half), x.slice(half)];  
-  let magnitudeOfA = Math.sqrt(a.reduce((total, num) => {return total + Math.pow(num, 2);}, 0));
-  let magnitudeOfB = Math.sqrt(b.reduce((total, num) => {return total + Math.pow(num, 2);}, 0));
-  let scalar = a.reduce((total, num, i)=>{return total + (num * b[i])}, 0);
-  return Math.acos(scalar / (magnitudeOfA * magnitudeOfB));
+const vectorAngle = (x, y) => {
+  let mX = Math.sqrt(x.reduce((acc, n) => acc + Math.pow(n, 2), 0));
+  let mY = Math.sqrt(y.reduce((acc, n) => acc + Math.pow(n, 2), 0));
+  return Math.acos(x.reduce((acc, n, i) => acc + n * y[i], 0) / (mX * mY));
 };
 ```
 
 ```js
-vectorAngle(3,4,4,3); // 0.283794109208328
+vectorAngle([3, 4], [4, 3]); // 0.283794109208328
 ```