Update snippets

snippets/all_equal.md

@@ -5,7 +5,7 @@ tags: list,beginner
 
 Checks if all elements in a list are equal.
 
-- Use `set()` to eliminate duplicate elements and then use `len()` to check if length is 1.
+- Use `set()` to eliminate duplicate elements and then use `len()` to check if length is `1`.
 
 ```py
 def all_equal(lst):

snippets/index_of_all.md

@@ -0,0 +1,18 @@
+---
+title: index_of_all
+tags: list,intermediate
+---
+
+Returns a list of indices of all the occurrences of an element in a list.
+
+- Use `enumerate()` and a list comprehension to check each element for equality with `value` and adding `i` to the result.
+
+```py
+def index_of_all(lst, value):
+  return [i for i, x in enumerate(lst) if x == value]
+```
+
+```py
+index_of_all([1, 2, 1, 4, 5, 1], 1) # [0, 2, 5]
+index_of_all([1, 2, 3, 4], 6) # [] 
+```

snippets/indices_of_occurence.md

@@ -1,19 +0,0 @@
----
-title: indices_of_occurrence
-tags: list,beginner
----
-
-Returns a list of indices of all the occurrences of an element in a list.
-
-- Use `enumerate()` to get index and value simultaneously while iterating.
-- Use `==` to check equality, if current element `val` is equal to `value`. Then `idx` to list.
-
-```py
-def indices_of_occurrence(lst, value):
-  return [idx for idx, val in enumerate(lst) if val == value]
-```
-
-```py
-indices_of_occurrence([1, 2, 1, 4, 5, 1], 1) # [0, 2, 5]
-indices_of_occurrence([1, 2, 3, 4], 6) # [] 
-```