Linting
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@ -6,10 +6,10 @@ Use arithmetic comparison to check if the given number is in the specified range
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If the second parameter, `end`, is not specified, the range is considered to be from `0` to `start`.
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```js
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const inRange = (n, start, end=null) => {
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if(end && start > end) end = [start, start=end][0];
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return (end == null) ? (n>=0 && n<start) : (n>=start && n<end);
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}
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const inRange = (n, start, end = null) => {
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if (end && start > end) end = [start, start = end][0];
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return (end == null) ? (n >= 0 && n < start) : (n >= start && n < end);
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};
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// inRange(3, 2, 5) -> true
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// inRange(3, 4) -> true
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// inRange(2, 3, 5) -> false
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