new arrray remove and concat issue fixed
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13
README.md
13
README.md
@ -10,6 +10,7 @@
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## Contents
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* [Anagrams of string (with duplicates)](#anagrams-of-string-with-duplicates)
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* [Array concatenation](#array-concatenation)
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* [Array difference](#array-difference)
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* [Array intersection](#array-intersection)
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* [Array union](#array-union)
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@ -57,7 +58,6 @@
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* [Promisify](#promisify)
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* [Random integer in range](#random-integer-in-range)
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* [Random number in range](#random-number-in-range)
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* [Randomize order of array](#randomize-order-of-array)
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* [Redirect to url](#redirect-to-url)
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* [Remove](#remove)
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* [Reverse a string](#reverse-a-string)
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@ -97,6 +97,15 @@ const anagrams = str => {
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// anagrams('abc') -> ['abc','acb','bac','bca','cab','cba']
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```
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### Array concatenation
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Use `Array.concat()` to concatenate and array with any additional arrays and/or values, specified in `args`.
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```js
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const ArrayConcat = (arr, ...args) => [].concat(arr, ...args);
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// ArrayConcat([1], [1, 2, 3, [4]]) -> [1, 2, 3, [4]]
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```
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### Array difference
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Create a `Set` from `b`, then use `Array.filter()` on `a` to only keep values not contained in `b`.
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@ -618,10 +627,12 @@ Remove elements from `arr` that are returns truthy. Use `Array.filter()` to find
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```js
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const remove = (arr, func) =>
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Array.isArray(arr) ?
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arr.filter(func).reduce((acc, val) => {
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arr.splice(arr.indexOf(val), 1)
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return acc.concat(val);
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}, [])
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: [];
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//remove([1, 2, 3, 4], n => n % 2 == 0) -> [2, 4]
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```
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@ -3,6 +3,6 @@
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Use `Array.concat()` to concatenate and array with any additional arrays and/or values, specified in `args`.
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```js
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const ArrayConcat = (arr, ...args) => arr.concat(...args);
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const ArrayConcat = (arr, ...args) => [].concat(arr, ...args);
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// ArrayConcat([1], [1, 2, 3, [4]]) -> [1, 2, 3, [4]]
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```
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@ -4,9 +4,11 @@ Remove elements from `arr` that are returns truthy. Use `Array.filter()` to find
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```js
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const remove = (arr, func) =>
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Array.isArray(arr) ?
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arr.filter(func).reduce((acc, val) => {
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arr.splice(arr.indexOf(val), 1)
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return acc.concat(val);
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}, [])
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: [];
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//remove([1, 2, 3, 4], n => n % 2 == 0) -> [2, 4]
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```
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