Fixes is_anagram, fixes #190

This commit is contained in:
Pablo Baeyens
2020-03-19 12:41:52 +01:00
parent f54b49aea7
commit 65b9cad729

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@ -5,16 +5,20 @@ tags: string,intermediate
Checks if a string is an anagram of another string (case-insensitive, ignores spaces, punctuation and special characters). Checks if a string is an anagram of another string (case-insensitive, ignores spaces, punctuation and special characters).
Use `s.replace()` to remove spaces from both strings. Filter out non-alphanumeric characters and transform each character to its lowercase version.
Compare the lengths of the two strings, return `False` if they are not equal. Use a `collections.Counter` to count the resulting characters and compare the results.
Use `sorted()` on both strings and compare the results.
```py ```py
from collections import Counter
def is_anagram(s1, s2): def is_anagram(s1, s2):
_str1, _str2 = s1.replace(" ", ""), s2.replace(" ", "") return Counter(
return False if len(_str1) != len(_str2) else sorted(_str1.lower()) == sorted(_str2.lower()) c.lower() for c in s1 if c.isalnum()
) == Counter(
c.lower() for c in s2 if c.isalnum()
)
``` ```
```py ```py
is_anagram("anagram", "Nag a ram") # True is_anagram("#anagram", "Nag a ram!") # True
``` ```