diff --git a/snippets/sort_by_indexes.md b/snippets/sort_by_indexes.md
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+---
+title: sort_by_indexes
+tags: list,sort,intermediate
+---
+
+Sorts one list based on another list containing the desired indexes.
+
+Use `zip()` and `sorted()` to combine and sort the two lists, based on the values of `indexes`.
+Use a list comprehension to get the first element of each pair from the result.
+
+```py
+def sort_by_indexes(lst, indexes):
+  return [val for _, val in sorted(zip(indexes, lst), key = lambda x: x[0])]
+```
+
+```py
+a = ['eggs', 'bread', 'oranges', 'jam', 'apples', 'milk']
+b = [3, 2, 6, 4, 1, 5]
+sort_by_indexes(a, b) # ['apples', 'bread', 'eggs', 'jam', 'milk', 'oranges']
+```
diff --git a/snippets/sort_list_based_on_another_list.md b/snippets/sort_list_based_on_another_list.md
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----
-title: sort_list_based_on_another_list
-tags: list,sort,intermediate
----
-
-Sorts one list based on given indices in another list and returns the sorted list of values.
-
-Use list comprehension to get values after using `zip` and `sorted` function based on given `key` with lambda function that returns the index.
-
-```py
-def sort_list_based_on_another_list(list_to_sort, index_list):
-  return [val for i, val in sorted(zip(index_list, list_to_sort), key = lambda x: x[0])]
-```
-
-```py
-a = ['eggs', 'bread', 'oranges', 'jam', 'apples', 'milk']
-b = [3, 2, 6, 4, 1, 5]
-sort_list_based_on_another_list(a, b) # ['apples', 'bread', 'eggs', 'jam', 'milk', 'oranges']
-```