If using ES6, use template litorals
Probably being pernickety. But if we're using ES6, you could just use a template litoral instead of string concat? Not sure if the litoral version is a bit more difficult to read mind you.
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@ -6,7 +6,7 @@ Convert the number to a string, using spread operators in ES6(`[...string]`) bui
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Use `Array.map()` and `parseInt()` to transform each value to an integer.
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```js
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const digitize = n => [...('' + n)].map(i => parseInt(i));
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const digitize = n => [...(`${n}`)].map(i => parseInt(i));
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```
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```js
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