Add reverse to sort_by_indexes

snippets/sort_by_indexes.md

@@ -1,20 +1,22 @@
 ---
 title: sort_by_indexes
-tags: list,sort,intermediate
+tags: list,intermediate
 ---
 
 Sorts one list based on another list containing the desired indexes.
 
 - Use `zip()` and `sorted()` to combine and sort the two lists, based on the values of `indexes`.
 - Use a list comprehension to get the first element of each pair from the result.
+- Use the `reverse` parameter in `sorted()` to sort the dictionary in reverse order, based on the third argument.
 
 ```py
-def sort_by_indexes(lst, indexes):
-  return [val for _, val in sorted(zip(indexes, lst), key = lambda x: x[0])]
+def sort_by_indexes(lst, indexes, reverse = False):
+  return [val for _, val in sorted(zip(indexes, lst), key = lambda x: x[0], reverse = reverse)]
 ```
 
 ```py
 a = ['eggs', 'bread', 'oranges', 'jam', 'apples', 'milk']
 b = [3, 2, 6, 4, 1, 5]
 sort_by_indexes(a, b) # ['apples', 'bread', 'eggs', 'jam', 'milk', 'oranges']
+sort_by_indexes(a, b, True) # ['oranges', 'milk', 'jam', 'eggs', 'bread', 'apples']
 ```