return default index when not found
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@ -4,15 +4,17 @@ Returns the index of the last element for which the provided function returns a
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Use `Array.prototype.map()` to map each element to an array with its index and value.
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Use `Array.prototype.filter()` to remove elements for which `fn` returns falsy values, `Array.prototype.pop()` to get the last one.
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`-1` is the default value when not found.
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```js
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const findLastIndex = (arr, fn) =>
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arr
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(arr
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.map((val, i) => [i, val])
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.filter(([i, val]) => fn(val, i, arr))
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.pop()[0];
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.pop() || [-1])[0];
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```
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```js
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findLastIndex([1, 2, 3, 4], n => n % 2 === 1); // 2 (index of the value 3)
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findLastIndex([1, 2, 3, 4], n => n === 5); // -1 (default value when not found)
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```
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@ -364,10 +364,10 @@ const filterNonUniqueBy = (arr, fn) =>
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const findKey = (obj, fn) => Object.keys(obj).find(key => fn(obj[key], key, obj));
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const findLast = (arr, fn) => arr.filter(fn).pop();
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const findLastIndex = (arr, fn) =>
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arr
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(arr
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.map((val, i) => [i, val])
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.filter(([i, val]) => fn(val, i, arr))
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.pop()[0];
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.pop() || [-1])[0];
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const findLastKey = (obj, fn) =>
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Object.keys(obj)
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.reverse()
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@ -6,3 +6,6 @@ test('findLastIndex is a Function', () => {
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test('Finds last index for which the given function returns true', () => {
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expect(findLastIndex([1, 2, 3, 4], n => n % 2 === 1)).toBe(2);
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});
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test('Return default index when not found', () => {
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expect(findLastIndex([1, 2, 3, 4], n => n === 5)).toBe(-1);
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});
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