Avoid confusing prototype methods for static methods

Correct: `Array.from()` (it’s a static method)
Incorrect: `Array.join()` (doesn’t exist; it’s a prototype method)

This patch uses the common `#` syntax to denote `.prototype.`.

snippets/unzipWith.md

@@ -2,9 +2,9 @@
 
 Creates an array of elements, ungrouping the elements in an array produced by [zip](#zip) and applying the provided function.
 
-Use `Math.max.apply()` to get the longest subarray in the array, `Array.map()` to make each element an array.
-Use `Array.reduce()` and `Array.forEach()` to map grouped values to individual arrays.
-Use `Array.map()` and the spread operator (`...`) to apply `fn` to each individual group of elements.
+Use `Math.max.apply()` to get the longest subarray in the array, `Array.prototype.map()` to make each element an array.
+Use `Array.prototype.reduce()` and `Array.prototype.forEach()` to map grouped values to individual arrays.
+Use `Array.prototype.map()` and the spread operator (`...`) to apply `fn` to each individual group of elements.
 
 ```js
 const unzipWith = (arr, fn) =>