Travis build: 539

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30secondsofcode
2018-09-27 15:13:22 +00:00
parent aa15eada60
commit b44b539b40
13 changed files with 58 additions and 15 deletions

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@ -168,6 +168,7 @@ average(1, 2, 3);
* [`remove`](#remove)
* [`sample`](#sample)
* [`sampleSize`](#samplesize)
* [`shank`](#shank)
* [`shuffle`](#shuffle)
* [`similarity`](#similarity)
* [`sortedIndex`](#sortedindex)
@ -2353,6 +2354,38 @@ sampleSize([1, 2, 3], 2); // [3,1]
sampleSize([1, 2, 3], 4); // [2,3,1]
```
</details>
<br>[⬆ Back to top](#table-of-contents)
### shank
Has the same functionality as [`Array.prototype.splice()`](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice), but returning a new array instead of mutating the original array.
Use `Array.slice()` and `Array.concat()` to get a new array with the new contents after removing existing elements and/or adding new elements.
Omit the second argument, `index`, to start at `0`.
Omit the third argument, `delCount`, to remove `0` elements.
Omit the fourth argument, `elements`, in order to not add any new elements.
```js
const shank = (arr, index = 0, delCount = 0, ...elements) =>
arr
.slice(0, index)
.concat(elements)
.concat(arr.slice(index + delCount));
```
<details>
<summary>Examples</summary>
```js
const names = ['alpha', 'bravo', 'charlie'];
const namesAndDelta = shank(names, 1, 0, 'delta'); // [ 'alpha', 'delta', 'bravo', 'charlie' ]
const namesNoBravo = shank(names, 1, 1); // [ 'alpha', 'charlie' ]
console.log(names); // ['alpha', 'bravo', 'charlie']
```
</details>
<br>[⬆ Back to top](#table-of-contents)