Add mostPerformant snippet

This commit is contained in:
atomiks
2018-02-14 22:38:45 +11:00
parent 9ce2497765
commit c687c8a413
2 changed files with 34 additions and 0 deletions

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### mostPerformant
Returns the index of the function in an array of functions which executed the fastest.
Use `Array.map()` to generate an array where each value is the total time taken to execute the function
after `iterations` times. Use the difference in `performance.now()` values before and after to get the total time
in milliseconds to a high degree of accuracy.
Use `Math.min()` to find the minimum execution time, and return the index of that shortest time which
corresponds to the index of the most performant function. Omit the second argument, `iterations`, to use a default of 10,000 iterations. The more iterations, the more reliable the result but the longer it will take.
```js
const mostPerformant = (fns, iterations = 10000) => {
const times = fns.map(fn => {
const before = performance.now();
for (let i = 0; i < iterations; i++) fn();
return performance.now() - before;
});
return times.indexOf(Math.min(...times));
};
```
```js
mostPerformant([
() => {
// Loops through the entire array before returning `false`
[1, 2, 3, 4, 5, 6, 7, 8, 9, '10'].every(el => typeof el === 'number')
},
() => {
// Only needs to reach index `1` before returning false
[1, '2', 3, 4, 5, 6, 7, 8, 9, 10].every(el => typeof el === 'number')
}
]); // 1
```

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@ -158,6 +158,7 @@ memoize:function
merge:object,array
minBy:math,array,function
minN:array,math
mostPerformant:function
negate:function
nthArg:utility,function
nthElement:array