Removed array includes snippet (native JS alternative exists)
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README.md
14
README.md
@ -12,7 +12,6 @@
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### Array
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* [Array concatenation](#array-concatenation)
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* [Array difference](#array-difference)
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* [Array includes](#array-includes)
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* [Array intersection](#array-intersection)
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* [Array remove](#array-remove)
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* [Array sample](#array-sample)
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@ -153,19 +152,6 @@ const difference = (a, b) => { const s = new Set(b); return a.filter(x => !s.has
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[⬆ back to top](#table-of-contents)
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### Array includes
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Use `slice()` to offset the array/string and `indexOf()` to check if the value is included.
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Omit the last argument, `fromIndex`, to check the whole array/string.
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```js
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const includes = (collection, val, fromIndex=0) => collection.slice(fromIndex).indexOf(val) != -1;
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// includes("30-seconds-of-code", "code") -> true
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// includes([1, 2, 3, 4], [1, 2], 1) -> false
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```
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[⬆ back to top](#table-of-contents)
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### Array intersection
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Create a `Set` from `b`, then use `Array.filter()` on `a` to only keep values contained in `b`.
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@ -1,11 +0,0 @@
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### Array includes
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Use `slice()` to offset the array/string and `indexOf()` to check if the value is included.
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Omit the last argument, `fromIndex`, to check the whole array/string.
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In [ES6](http://www.ecma-international.org/ecma-262/7.0/#sec-array.prototype.includes), you can use a similar native `.includes()` function.
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```js
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const includes = (collection, val, fromIndex=0) => collection.slice(fromIndex).indexOf(val) != -1;
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// includes("30-seconds-of-code", "code") -> true
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// includes([1, 2, 3, 4], [1, 2], 1) -> false
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```
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@ -2,7 +2,6 @@
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anagrams-of-string-(with-duplicates):string
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array-concatenation:array
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array-difference:array
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array-includes:array
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array-intersection:array
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array-remove:array
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array-sample:array
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