Travis build: 1670

This commit is contained in:
30secondsofcode
2019-12-31 11:21:41 +00:00
parent e4fcaabed8
commit d51b430122
13 changed files with 163 additions and 119 deletions

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@ -1037,7 +1037,7 @@
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@ -2864,7 +2879,7 @@
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@ -3425,7 +3440,7 @@
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@ -1693,10 +1693,10 @@
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@ -4249,6 +4249,31 @@
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"id": "isPowerOfTwo",
"title": "isPowerOfTwo",
"type": "snippet",
"attributes": {
"fileName": "isPowerOfTwo.md",
"text": "Returns `true` if the given number is a power of `2`, `false` otherwise.\n\nUse the bitwise binary AND operator (`&`) to determine if `n is a power of `2. \nAdditionally, check that `n` is not falsy.\n\n",
"codeBlocks": {
"es6": "const isPowerOfTwo = n => !!n && (n & (n - 1)) == 0;",
"es5": "var isPowerOfTwo = function isPowerOfTwo(n) {\n return !!n && (n & n - 1) == 0;\n};",
"example": "isPowerOfTwo(0); // false\nisPowerOfTwo(1); // true\nisPowerOfTwo(8); // true"
},
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@ -4680,10 +4705,10 @@
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@ -6150,7 +6175,7 @@
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"example": "const sum = pipeAsyncFunctions(\n x => x + 1,\n x => new Promise(resolve => setTimeout(() => resolve(x + 2), 1000)),\n x => x + 3,\n async x => (await x) + 4\n);\n(async () => {\n console.log(await sum(5)); // 15 (after one second)\n})();"
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@ -6160,10 +6185,10 @@
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@ -9,7 +9,7 @@ Use the bitwise binary AND operator (`&`) to determine if `n is a power of `2.
Additionally, check that `n` is not falsy.
```js
const isPowerOfTwo = n => !!n && ((n & (n - 1)) == 0);
const isPowerOfTwo = n => !!n && (n & (n - 1)) == 0;
```
```js

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@ -11,7 +11,6 @@ Omit the second argument, `separator`, to use a default separator of `','`.
Omit the third argument, `end`, to use the same value as `separator` by default.
```js
const join = (arr, separator = ',', end = separator) =>
arr.reduce(
(acc, val, i) =>

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@ -10,7 +10,6 @@ Determine the `symbol` to be either `?` or `&` based on the `length` of `querySt
Return the `queryString` or an empty string when the `queryParameters` are falsy.
```js
const objectToQueryString = queryParameters => {
return queryParameters
? Object.entries(queryParameters).reduce((queryString, [key, val], index) => {

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@ -14,14 +14,13 @@ const pipeAsyncFunctions = (...fns) => arg => fns.reduce((p, f) => p.then(f), Pr
```
```js
const sum = pipeAsyncFunctions(
x => x + 1,
x => new Promise(resolve => setTimeout(() => resolve(x + 2), 1000)),
x => x + 3,
async x => (await x) + 4
);
(async() => {
(async () => {
console.log(await sum(5)); // 15 (after one second)
})();
```

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@ -9,6 +9,7 @@ Use `Array.prototype.filter()` to find array elements that return truthy values
The `func` is invoked with three arguments (`value, index, array`).
```js
const remove = (arr, func) =>
Array.isArray(arr)
? arr.filter(func).reduce((acc, val) => {

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@ -12,7 +12,6 @@ Use `size` of a [`Blob` object](https://developer.mozilla.org/en-US/docs/Web/API
Split strings into array of characters with `split('')` and return its length.
```js
const size = val =>
Array.isArray(val)
? val.length

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@ -599,7 +599,7 @@ const isObject = obj => obj === Object(obj);
const isObjectLike = val => val !== null && typeof val === 'object';
const isOdd = num => num % 2 === 1;
const isPlainObject = val => !!val && typeof val === 'object' && val.constructor === Object;
const isPowerOfTwo = n => !!n && ((n & (n - 1)) == 0);
const isPowerOfTwo = n => !!n && (n & (n - 1)) == 0;
const isPrime = num => {
const boundary = Math.floor(Math.sqrt(num));
for (var i = 2; i <= boundary; i++) if (num % i === 0) return false;

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@ -1587,6 +1587,13 @@
],
"description": "Checks if the provided value is an object created by the Object constructor.\n\nCheck if the provided value is truthy, use `typeof` to check if it is an object and `Object.constructor` to make sure the constructor is equal to `Object`.\n"
},
"isPowerOfTwo": {
"prefix": "30s_isPowerOfTwo",
"body": [
"const isPowerOfTwo = n => !!n && (n & (n - 1)) == 0;"
],
"description": "Returns `true` if the given number is a power of `2`, `false` otherwise.\n\nUse the bitwise binary AND operator (`&`) to determine if `n is a power of `2. \nAdditionally, check that `n` is not falsy.\n"
},
"isPrime": {
"prefix": "30s_isPrime",
"body": [