diff --git a/test/filterNonUnique.test.js b/test/filterNonUnique.test.js index 459c67282..2d94bb77f 100644 --- a/test/filterNonUnique.test.js +++ b/test/filterNonUnique.test.js @@ -7,3 +7,10 @@ test('filterNonUnique is a Function', () => { test('Filters out the non-unique values in an array', () => { expect(filterNonUnique([1, 2, 2, 3, 4, 4, 5])).toEqual([1, 3, 5]); }); +test('Works with multiple types of values in the same array', () => { + expect(filterNonUnique([1, 2, 2, 3, 4, 4, 5, true, 'repeated text', 'repeated text', 'unique text'])).toEqual([1, 3, 5, true, 'unique text']); +}); +test('No error on empty array', () => { + expect(filterNonUnique([])).toEqual([]); +}); + diff --git a/test/squareSum.test.js b/test/squareSum.test.js index 13b31a2af..69b6b8962 100644 --- a/test/squareSum.test.js +++ b/test/squareSum.test.js @@ -7,3 +7,11 @@ test('squareSum is a Function', () => { test('squareSum returns the proper result', () => { expect(squareSum(2, 3, 4)).toBe(29); }); + +test('works with negative numbers', () => { + expect(squareSum(-2, 3, -4)).toBe(29); +}); + +test('NaN when parameters have text', () => { + expect(squareSum(-2, 3, -4, 'text')).toBe(NaN); +}); diff --git a/test/uniqueSymmetricDifference.test.js b/test/uniqueSymmetricDifference.test.js index d9fa598b6..eaf97a6a1 100644 --- a/test/uniqueSymmetricDifference.test.js +++ b/test/uniqueSymmetricDifference.test.js @@ -10,3 +10,13 @@ test('Returns the symmetric difference between two arrays.', () => { test('Does not return duplicates from one array', () => { expect(uniqueSymmetricDifference([1, 2, 2], [1, 3, 1])).toEqual([2, 3]); }); +test('Works with different size arrays', () => { + expect(uniqueSymmetricDifference([1, 2, 2, 4], [1, 3, 1, 4, 5, 6])).toEqual([2, 3, 5, 6]); +}); +test('Works with different types in the same array', () => { + expect(uniqueSymmetricDifference([1, 2, 'duplicate text', 'unique text'], [1, 3, 'duplicate text'])).toEqual([2, 'unique text', 3]); +}); +test('Works when one array is empty', () => { + expect(uniqueSymmetricDifference([1, 2, 2, 3], [])).toEqual([1, 2, 3]); +}); +