diff --git a/snippets/transpose.md b/snippets/transpose.md
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-## Make a transpose matrix
-
-```python
-def transpose(l):
-    return list(zip(*l))
-
-l = [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
-print(transpose(l))
-# Output: [(1, 4, 7, 10), (2, 5, 8, 11), (3, 6, 9, 12)]
-```
diff --git a/snippets/transpose_matrix.md b/snippets/transpose_matrix.md
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+---
+title: transpose_matrix
+tags: matrix,list,zip,intermediate
+---
+
+Python `zip()` function takes the iterable elements as input and returns the iterator.
+Since zip funtion returns a `zip object`, we can cast it as list wit `list()`.
+```py
+list(zip([1,2,3],['a','b','c'], [True, False, True]))
+# Output: [(1, 'a', True), (2, 'b', False), (3, 'c', True)]
+```
+
+Using `*list`, we can access to each element of the list
+```py
+[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
+# Output: [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
+*[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
+# Output: [1, 2, 3] [4, 5, 6] [7, 8, 9] [10, 11, 12]
+```
+
+Combining these two elements we can transpose a matrix. We can access to each row of the matrix using the operator `*` to use them as args of `zip()` function.
+
+```py
+def transpose_matrix(l:list):
+    return list(zip(*l))
+
+print(transpose_matrix([[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]))
+# Output: [(1, 4, 7, 10), (2, 5, 8, 11), (3, 6, 9, 12)]
+```