Travis build: 920
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@ -5,15 +5,19 @@ If `num` is greater than `1` returns the plural form of the given string, else r
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Check if `num` is positive. Throw an appropriate `Error` if not, return the appropriate string otherwise.
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Omit the third argument, `items`, to use a default plural form same as `item` suffixed with a single `'s'`.
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``` js
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const pluralize = (num, item, items = item+'s') =>
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num <= 0 ? (() => {throw new Error(`'num' should be >= 1. Value povided was ${num}.`)})() : num === 1 ? item : items;
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```js
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const pluralize = (num, item, items = item + 's') =>
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num <= 0
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? (() => {
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throw new Error(`'num' should be >= 1. Value povided was ${num}.`);
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})()
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: num === 1 ? item : items;
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```
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```js
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pluralize(1,'apple','apples'); // 'apple'
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pluralize(3,'apple','apples'); // 'apples'
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pluralize(2,'apple'); // 'apples'
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pluralize(0,'apple','apples'); // Gives error
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pluralize(-3,'apple','apples'); // Gives error
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pluralize(1, 'apple', 'apples'); // 'apple'
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pluralize(3, 'apple', 'apples'); // 'apples'
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pluralize(2, 'apple'); // 'apples'
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pluralize(0, 'apple', 'apples'); // Gives error
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pluralize(-3, 'apple', 'apples'); // Gives error
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```
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