### pluralize

If `num` is greater than `1` returns the plural form of the given string, else return the singular form.

Check if `num` is greater than `0`. Throw an appropriate `Error` if not, return the appropriate string otherwise.
Omit the third argument, `items`, to use a default plural form same as `item` suffixed with a single `'s'`.

```js
const pluralize = (num, item, items = item + 's') =>
  num <= 0
    ? (() => {
        throw new Error(`'num' should be >= 1. Value povided was ${num}.`);
      })()
    : num === 1 ? item : items;
```

```js
pluralize(1, 'apple', 'apples'); // 'apple'
pluralize(3, 'apple', 'apples'); // 'apples'
pluralize(2, 'apple'); // 'apples'
pluralize(0, 'apple', 'apples'); // Gives error
pluralize(-3, 'apple', 'apples'); // Gives error
```