8 lines
278 B
JavaScript
8 lines
278 B
JavaScript
const fibonacciUntilNum = num => {
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let n = Math.ceil(Math.log(num * Math.sqrt(5) + 1 / 2) / Math.log((Math.sqrt(5) + 1) / 2));
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return Array.from({ length: n }).reduce(
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(acc, val, i) => acc.concat(i > 1 ? acc[i - 1] + acc[i - 2] : i),
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[]
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);
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};
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module.exports = fibonacciUntilNum; |