Updated function with help from @skatcat31

This commit is contained in:
Arjun Mahishi
2017-12-20 12:30:56 +05:30
parent dc25690644
commit 67ec42411b

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@ -5,10 +5,7 @@ Checks if the given number is an armstrong number or not.
Convert the given number into array of digits. Use `Math.pow()` to get the appropriate power for each digit and sum them up. If the sum is equal to the number itself, return `true` otherwise `false`.
```js
const isArmstrongNumber = num => {
let arr = (num+"").split("");
return arr.reduce((a, d) => parseInt(a) + Math.pow(parseInt( d ), arr.length), 0) == num ? true : false
}
const isArmstrongNumber = digits => ( arr => arr.reduce( ( a, d ) => a + Math.pow( parseInt( d ), arr.length ), 0 ) == digits ? true : false )( ( digits+'' ).split( '' ) )
// isArmstrongNumber(1634) -> true
// isArmstrongNumber(371) -> true