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30-seconds-of-code/snippets/converge.md
Mathias Bynens 8ee50178f3 Avoid confusing prototype methods for static methods
Correct: `Array.from()` (it’s a static method)
Incorrect: `Array.join()` (doesn’t exist; it’s a prototype method)

This patch uses the common `#` syntax to denote `.prototype.`.
2018-09-28 15:44:12 -04:00

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### converge
Accepts a converging function and a list of branching functions and returns a function that applies each branching function to the arguments and the results of the branching functions are passed as arguments to the converging function.
Use `Array.prototype.map()` and `Function.prototype.apply()` to apply each function to the given arguments.
Use the spread operator (`...`) to call `coverger` with the results of all other functions.
```js
const converge = (converger, fns) => (...args) => converger(...fns.map(fn => fn.apply(null, args)));
```
```js
const average = converge((a, b) => a / b, [
arr => arr.reduce((a, v) => a + v, 0),
arr => arr.length
]);
average([1, 2, 3, 4, 5, 6, 7]); // 4
```