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30-seconds-of-code/snippets/unionWith.md
30secondsofcode 87e1cbdcbd Travis build: 1368
2018-01-24 10:21:11 +00:00

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### unionWith
Returns every element that exists in any of the two arrays once, using a provided comparator function.
Create a `Set` with all values of `a` and values in `b` for which the comparator finds no matches in `a`, using `Array.findIndex()`.
```js
const unionWith = (a, b, comp) =>
Array.from(new Set([...a, ...b.filter(x => a.findIndex(y => comp(x, y)) === -1)]));
```
```js
unionWith([1, 1.2, 1.5, 3, 0], [1.9, 3, 0, 3.9], (a, b) => Math.round(a) === Math.round(b)); // [1, 1.2, 1.5, 3, 0, 3.9]
```