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30-seconds-of-code/snippets/bifurcate.md
Angelos Chalaris cb8bbd9745 Update formatting
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2020-01-03 13:06:54 +02:00

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title, tags
title tags
bifurcate list,intermediate

Splits values into two groups. If an element in filter is True, the corresponding element in the collection belongs to the first group; otherwise, it belongs to the second group.

Use list comprehension and enumerate() to add elements to groups, based on filter.

def bifurcate(lst, filter):
  return [
    [x for i, x in enumerate(lst) if filter[i] == True],
    [x for i, x in enumerate(lst) if filter[i] == False]
  ]
bifurcate(['beep', 'boop', 'foo', 'bar'], [True, True, False, True]) # [ ['beep', 'boop', 'bar'], ['foo'] ]