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30-seconds-of-code/snippets/bifurcate_by.md
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2020-01-03 13:06:54 +02:00

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title, tags
title tags
bifurcate_by list,function,intermediate

Splits values into two groups according to a function, which specifies which group an element in the input list belongs to. If the function returns True, the element belongs to the first group; otherwise, it belongs to the second group.

Use list comprehension to add elements to groups, based on fn.

def bifurcate_by(lst, fn):
  return [
    [x for x in lst if fn(x)],
    [x for x in lst if not fn(x)]
  ]
bifurcate_by(
  ['beep', 'boop', 'foo', 'bar'], 
  lambda x: x[0] == 'b'
) # [ ['beep', 'boop', 'bar'], ['foo'] ]