356 B
356 B
title, tags
| title | tags |
|---|---|
| intersection | list,beginner |
Returns a list of elements that exist in both lists.
Create a set from b, then use list comprehension on a to only keep values contained in both lists.
def intersection(a, b):
_b = set(b)
return [item for item in a if item in _b]
intersection([1, 2, 3], [4, 3, 2]) # [2, 3]