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30-seconds-of-code/snippets/sortedLastIndexBy.md
2018-01-26 13:39:09 +02:00

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### sortedLastIndexBy
Returns the highest index at which value should be inserted into array in order to maintain its sort order, based on a provided iterator function.
Check if the array is sorted in descending order (loosely).
Use `Array.reverse()` and `Array.findIndex()` to find the appropriate last index where the element should be inserted, based on the iterator function `fn`..
```js
const sortedLastIndexBy = (arr, n, fn) => {
const isDescending = fn(arr[0]) > fn(arr[arr.length - 1]);
const val = fn(n);
const index = arr
.map((val, i) => [i, fn(val)])
.reverse()
.findIndex(el => (isDescending ? val <= el[1] : val >= el[1]));
return index === -1 ? 0 : arr.length - index;
};
```
```js
sortedLastIndexBy([{ 'x': 4 }, { 'x': 5 }], { 'x': 4 }, o => o.x); // 1
```