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30-seconds-of-code/snippets/unionBy.md
2022-05-14 15:55:07 +03:00

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---
title: Mapped array union
tags: array
expertise: intermediate
cover: blog_images/lake-church.jpg
firstSeen: 2018-01-24T12:19:41+02:00
lastUpdated: 2020-10-22T20:24:44+03:00
---
Returns every element that exists in any of the two arrays at least once, after applying the provided function to each array element of both.
- Create a `Set` by applying all `fn` to all values of `a`.
- Create a `Set` from `a` and all elements in `b` whose value, after applying `fn` does not match a value in the previously created set.
- Return the last set converted to an array.
```js
const unionBy = (a, b, fn) => {
const s = new Set(a.map(fn));
return Array.from(new Set([...a, ...b.filter(x => !s.has(fn(x)))]));
};
```
```js
unionBy([2.1], [1.2, 2.3], Math.floor); // [2.1, 1.2]
unionBy([{ id: 1 }, { id: 2 }], [{ id: 2 }, { id: 3 }], x => x.id)
// [{ id: 1 }, { id: 2 }, { id: 3 }]
```