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30-seconds-of-code/snippets/isArraySorted.md
2018-01-01 17:28:34 +00:00

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### functionName
Returns `1` if the array is sorted in ascending order, `-1` if it is sorted in descending order or `0` if it is not sorted.
Calculate the ordering `direction` for the first two elements.
Use `Object.entries()` to loop over array objects and compare them in pairs.
Return `0` if the `direction` changes or the `direction` if the last element is reached.
```js
const isArraySorted = arr => {
const direction = arr[0] > arr[1] ? -1 : 1;
for (let [i, val] of arr.entries())
if (i === arr.length - 1) return direction;
else if ((val - arr[i + 1]) * direction > 0) return 0;
};
```
```js
isArraySorted([0, 1, 2, 3]); // 1
isArraySorted([0, 1, 2, 2]); // 1
isArraySorted([4, 3, 2]); // -1
isArraySorted([4, 3, 5]); // 0
```