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30-seconds-of-code/javascript/snippets/union-with.md
2023-05-01 22:35:56 +03:00

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---
title: Array union based on function
type: snippet
tags: [array]
cover: orange-coffee-4
dateModified: 2020-10-22T20:24:44+03:00
---
Returns every element that exists in any of the two arrays at least once, using a provided comparator function.
- Create a `Set` with all values of `a` and values in `b` for which the comparator finds no matches in `a`, using `Array.prototype.findIndex()`.
```js
const unionWith = (a, b, comp) =>
Array.from(
new Set([...a, ...b.filter(x => a.findIndex(y => comp(x, y)) === -1)])
);
```
```js
unionWith(
[1, 1.2, 1.5, 3, 0],
[1.9, 3, 0, 3.9],
(a, b) => Math.round(a) === Math.round(b)
);
// [1, 1.2, 1.5, 3, 0, 3.9]
```