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30-seconds-of-code/snippets/sortedLastIndexBy.md
Isabelle Viktoria Maciohsek 27c168ce55 Bake date into snippets
2021-06-13 13:55:00 +03:00

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---
title: sortedLastIndexBy
tags: array,intermediate
firstSeen: 2018-01-26T13:39:09+02:00
lastUpdated: 2020-10-22T20:24:30+03:00
---
Finds the highest index at which a value should be inserted into an array in order to maintain its sort order, based on a provided iterator function.
- Loosely check if the array is sorted in descending order.
- Use `Array.prototype.map()` to apply the iterator function to all elements of the array.
- Use `Array.prototype.reverse()` and `Array.prototype.findIndex()` to find the appropriate last index where the element should be inserted, based on the provided iterator function.
```js
const sortedLastIndexBy = (arr, n, fn) => {
const isDescending = fn(arr[0]) > fn(arr[arr.length - 1]);
const val = fn(n);
const index = arr
.map(fn)
.reverse()
.findIndex(el => (isDescending ? val <= el : val >= el));
return index === -1 ? 0 : arr.length - index;
};
```
```js
sortedLastIndexBy([{ x: 4 }, { x: 5 }], { x: 4 }, o => o.x); // 1
```