30-seconds-of-code/snippets/minN.md

minN

Returns the n minimum elements from the provided array. If n is greater than or equal to the provided array's length, then return the original array (sorted in ascending order).

Use Array.sort() combined with the spread operator (...) to create a shallow clone of the array and sort it in ascending order. Use Array.slice() to get the specified number of elements. Omit the second argument, n, to get a one-element array.

const minN = (arr, n = 1) => [...arr].sort((a, b) => a - b).slice(0, n);

minN([1, 2, 3]); // [1]
minN([1, 2, 3], 2); // [1,2]