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30-seconds-of-code/snippets/anagrams-of-string-(with-duplicates).md
Angelos Chalaris b81bbb65b1 Merge pull request #35 from jobsamuel/master
refactor(anagrams): improve code legibility
2017-12-12 18:01:33 +02:00

688 B

Anagrams of string (with duplicates)

Use recursion. For each letter in the given string, create all the partial anagrams for the rest of its letters. Use map() to combine the letter with each partial anagram, then reduce() to combine all anagrams in one array. Base cases are for string length equal to 2 or 1.

const anagrams = str => {
  if(str.length <= 2)  return str.length === 2 ? [str, str[1] + str[0]] : [str];
  return str.split('').reduce( (acc, letter, index) => {
    anagrams(str.slice(0, index) + str.slice(index + 1)).map( value => acc.push(letter + value) );
    return acc;
  }, []);
}
// anagrams('abc') -> ['abc','acb','bac','bca','cab','cba']