18 lines
298 B
Markdown
18 lines
298 B
Markdown
---
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title: every_nth
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tags: list,beginner
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---
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Returns every nth element in a list.
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- Use `[nth-1::nth]` to create a new list that contains every nth element of the given list.
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```py
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def every_nth(lst, nth):
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return lst[nth - 1::nth]
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```
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```py
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every_nth([1, 2, 3, 4, 5, 6], 2) # [ 2, 4, 6 ]
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```
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