25 lines
681 B
Markdown
25 lines
681 B
Markdown
---
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title: bifurcate
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tags: list,intermediate
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firstSeen: 2019-08-20T12:37:06+03:00
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lastUpdated: 2020-11-02T19:27:07+02:00
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---
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Splits values into two groups, based on the result of the given `filter` list.
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- Use a list comprehension and `zip()` to add elements to groups, based on `filter`.
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- If `filter` has a truthy value for any element, add it to the first group, otherwise add it to the second group.
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```py
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def bifurcate(lst, filter):
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return [
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[x for x, flag in zip(lst, filter) if flag],
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[x for x, flag in zip(lst, filter) if not flag]
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]
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```
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```py
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bifurcate(['beep', 'boop', 'foo', 'bar'], [True, True, False, True])
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# [ ['beep', 'boop', 'bar'], ['foo'] ]
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```
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