25 lines
642 B
Markdown
25 lines
642 B
Markdown
---
|
|
title: have_same_contents
|
|
tags: list,intermediate
|
|
firstSeen: 2020-03-15T12:54:08+02:00
|
|
lastUpdated: 2020-11-02T19:28:05+02:00
|
|
---
|
|
|
|
Checks if two lists contain the same elements regardless of order.
|
|
|
|
- Use `set()` on the combination of both lists to find the unique values.
|
|
- Iterate over them with a `for` loop comparing the `count()` of each unique value in each list.
|
|
- Return `False` if the counts do not match for any element, `True` otherwise.
|
|
|
|
```py
|
|
def have_same_contents(a, b):
|
|
for v in set(a + b):
|
|
if a.count(v) != b.count(v):
|
|
return False
|
|
return True
|
|
```
|
|
|
|
```py
|
|
have_same_contents([1, 2, 4], [2, 4, 1]) # True
|
|
```
|