740 B
740 B
pluralize
If num is greater than 1 returns the plural form of the given string, else return the singular form.
Check if num is positive. Throw an appropriate Error if not, return the appropriate string otherwise.
Omit the third argument, items, to use a default plural form same as item suffixed with a single 's'.
const pluralize = (num, item, items = item+'s') =>
num <= 0 ? (() => {throw new Error(`'num' should be >= 1. Value povided was ${num}.`)})() : num === 1 ? item : items;
pluralize(1,'apple','apples'); // 'apple'
pluralize(3,'apple','apples'); // 'apples'
pluralize(2,'apple'); // 'apples'
pluralize(0,'apple','apples'); // Gives error
pluralize(-3,'apple','apples'); // Gives error