26 lines
733 B
Markdown
26 lines
733 B
Markdown
### anagrams
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Generates all anagrams of a string (contains duplicates).
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Use recursion.
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For each letter in the given string, create all the partial anagrams for the rest of its letters.
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Use `Array.map()` to combine the letter with each partial anagram, then `Array.reduce()` to combine all anagrams in one array.
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Base cases are for string `length` equal to `2` or `1`.
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```js
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const anagrams = str => {
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if (str.length <= 2) return str.length === 2 ? [str, str[1] + str[0]] : [str];
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return str
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.split('')
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.reduce(
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(acc, letter, i) =>
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acc.concat(anagrams(str.slice(0, i) + str.slice(i + 1)).map(val => letter + val)),
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[]
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);
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};
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```
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```js
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anagrams('abc'); // ['abc','acb','bac','bca','cab','cba']
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```
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